js获取url参数值

方法一：正则分析法
function getQueryString(name) {
var reg =new RegExp(“(^|&)”+ name +”=([^&]*)(&|$)”, “i”);
var r = window.location.search.substr(1).match(reg);
if (r !=null) return unescape(r[2]); returnnull;
}
这样调用：
alert(GetQueryString(“参数名1”));

alert(GetQueryString(“参数名2”));

alert(GetQueryString(“参数名3”));

//alert(GetQueryString("参数名"));
方法二：
<span style=”font-size: 16px;”>
<Script language=”javascript”>
function GetRequest() {
var url = location.search; //获取url中”?”符后的字串
var theRequest = new Object();
if (url.indexOf(“?”) != -1) {
var str = url.substr(1);
strs = str.split(“&”);
for(var i = 0; i < strs.length; i ++) {
theRequest[strs[i].split(“=”)[0]]=unescape(strs[i].split(“=”)[1]);
}
}
return theRequest;
}
</Script>
</span>
这样调用：
<Script language=”javascript”>
var Request =new Object();
Request = GetRequest();
var 参数1,参数2,参数3,参数N;
参数1 = Request[‘参数1’];
参数2 = Request[‘参数2’];
参数3 = Request[‘参数3’];
参数N = Request[‘参数N’];
</Script>